The slope-intercept form of the equation of a line that passes through point (-3,8) is y=-2/3x + 6. what ts the point-slope form of the equation for this line?

The point-slope equation of this line would be y - 8 = -2/3(x + 3)

Step-by-step explanation:

In order to find the equation of this line in point-slope form, we first need to find the slope of the line. Being as it is in slope-intercept form currently, we know the coefficient of x is the slope (-2/3). Now we can use the slope and the given point in the base form of point-slope form.

y - y1 = m(x - x1)

y - 8 = -2/3(x - -3)

y - 8 = -2/3(x + 3)

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option