What is the equation of a line that is perpendicular to 2x+y=−4 and passes through the point (2, −8) ?

Slope-intercept form:

y = mx + b

"m" is the slope, "b" is the y-intercept (the y value when x = 0)

You need to find "m" and "b".

For lines to be perpendicular, their slopes have to be the opposite/negative reciprocal (flipped sign and number)

For example:

Slope is 2

Perpendicular line's slope is -1/2

Slope is -2/3

Perpendicular line's slope is 3/2

Isolate the y in the given equation

2x + y = -4    Subtract 2x on both sides

y = -2x - 4

The given line's slope is -2, so the perpendicular line's slope is 1/2

y = 1/2x + b

To find "b", plug in the point (2,-8) into the equation

y = 1/2x + b

-8 = 1/2(2) + b

-8 = 1 + b

-9 = b

300pi

step-by-step explanation: