What is the center of the circle that has a diameter whose endpoints are (6, -4) and (18, 10)? (12, 7) (12, 6) (12, 3)

(12, 3)

Step-by-step explanation:

To answer this, we find the midpoint of the line segment (that is, of the diameter) connecting (6, -4) and (18, 10):

The formula for the midpoint gives us x-midpoint = (6+18)/2, or x-midpoint = 12.

The formula for the midpoint gives us y-midpoint = (-4+10)/2, or x-midpoint = (6)/2 = 3.

Thus, the center of this circle is at (x-midpoint), y-midpoint), or (12, 3).

The third answer choice is the correct one.

50-38=12

step-by-step explanation:

17.08

correct me if i am wrong.