One number is four more than twice a second number their differences is eleven find two numbers

x = 18

y = 7

Step-by-step explanation:

Equations

x = 2*y + 4              (1)

x - y = 11                  (2)

Solution

Add y to both sides of equation 2.

x - y + y = 11 + y

x = 11 + y                  (3)

Equate Equations 1 and 3 for x

2y + 4 = 11 + y              Subtract y from both sides

2y - y + 4 = 11 + y - y    Combine terms.

y + 4 = 11                       Subtract 4 from both sides.

y + 4 - 4 = 11 - 4

y = 7

Now use equation (1) to find x

x = 2y + 4

x = 2*(7) + 4

x = 14 + 4

x = 18

(18,7)

answer: y = 3/2 x - 3

y = 1/8 x - 3/4 that would be your correct option

step-by-step explanation: w

false

step-by-step explanation:

false : it can not go to 9 the highest that part can go is 7

here is your proof