The box plot compares marta’s and ani’s diving scores in the first several meets of the season. based on the data in the box plots, what is the best evidence to show which diver had greater overall success during the meets so far this season? ani was more successful because she had an outlier. marta was more successful because she received the highest score. ani was more successful because she had the greater measure of center. marta was more successful because she the had the greater total spread.

Marta was more successful because she had the greater total spread

Step-by-step explanation:

As it is clearly visible in the image that the total spread of Ani is from 4.5 to 9.5 but on the other hand the total spread of Marta is from 4 to 10 which is greater than that of Ani

So, Marta was more successful than Ani because of greater total spread

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)