Write an equation of the line thst passes through (2, -3) and is perpendicular to the line y= -2x - 3

Slope-intercept form:

y = mx + b

"m" is the slope, "b" is the y-intercept (the y value when x = 0)

You need to find "m" and "b".

For lines to be perpendicular, their slopes have to be the opposite/negative reciprocals (flipped sign and number)

For example:

slope is 3

perpendicular line's slope is -1/3

slope is -2/5

perpendicular line's slope is 5/2

The given line's slope is -2, so the perpendicular line's slope is 1/2.

y = 1/2x + b

To find "b", you plug in the point (2,-3) into the equation

y = 1/2x + b

-3 = 1/2(2) + b

-3 = 1 + b   Subtract 1 on both sides

-4 = b