Sopve each quadratic equation 1) 3x^2+6x+6=0

Hello from MrBillDoesMath!

 There is no real solution to equation 1)

(It's implied that other equations are involved in this problem The other equations were not provided by the author)

Discussion:

Divide each side of the equation by 3. This gives

x^2 + 2x + 2 = 0

or

(x^2 + 2x + 1) + 1 = 0

or

(x+1)^2 +1 = 0

or

(x+1)^2 = -1

But any number squared is positive so the last equation has NO solution

Thank you,

MrB

part a: 1.08

part b: 27.59