Ineed to find the equation of the line that has the same y intercept as the line y-8x+3=0 and is parallel to the line 4x-9y=1

Step-by-step explanation:

How do you find the equation of a line parallel to another line?

Method 1: Using Slope Intercept Form

Substitute the slope from original line (3 in this case) into the equation of the line y = 3x + b.

Substitute the given point (1,7) into the x and y values 7 = 3(1) + b.

Solve for b (the y-intercept)

Substitute this value for 'b' in the slope intercept form equation y = 3x + 4.

How do you find the Y intercept of a parallel line?

Step 1: Find the slope of the line. To find the slope of the given line we need to get the line into slope-intercept form (y = mx + b), which means we need to solve for y: The slope of the line 3x – 5y = 9 is m = 3/5. Therefore, the slope of the line parallel to this line would have to be m = 3/5.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752