The area of a triangle piece of aluminum sheeting is 120 inches^2. the base of the triangle is 4 inches more then twice the height. find the length of the base and height of aluminum triangle.

Length of the base of aluminum triangle is 24 inch

Height  of aluminum triangle is 10 inch

Step-by-step explanation:

Let's assume height of  triangle is h

we are given

The base of the triangle is 4 inches more then twice the height

so, we get length of the base of triangle

now, we can find area of triangle

now, we can plug b

now, we are given that area =120inch^2

so, we can set it

now, we can solve for h

we can factor out 2

now, we can factor it

we can set each terms =0

and then we can solve for h

we know that height can never be negative

so, we will only consider h=10

now, we can find b

Length of the base of aluminum triangle is 24 inch

Height  of aluminum triangle is 10 inch

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

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step-by-step explanation: