Joanne has a cylindrical, above ground pool. the depth (height) of the pool is 1/2 of its radius, and the volume is 1570 cubic feet. what is the area of its bottom floor? include equations or inequalities related.

We know that Volume of Cylinder is given by : πr²h

Where : 'r' is the Radius of the Cylinder

             'h' is the Height or Depth of the Cylinder

Given : The Height of the Pool is Half of its Radius

⇒ Height of the Pool =  

Given : The Volume of the Pool = 1570 feet³

⇒ πr²h = 1570

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As : Area of the Bottom of the Pool is Circular

We know that Area of Circle is given by : πr²

⇒ Area of the Bottom Floor = π × 10² = 314.15 feet²

answer: i believe it’s 245.04

step-by-step explanation:

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -