Two cars leave towns 360 kilometers apart at the same time and travel toward each other. one car's rate is 10 kilometers per hour more than the other's. if they meet in 2 hours, what is the rate of the faster car? do not do any rounding.

Remark

Let the slower car = r.

Let the faster car = r + 10

t = 2 hours

Equation

(r )* 2 + (r + 10)*2 = 360

Sub and solve

2r + 2r +  20 = 360                Remove the brackets. Combine like terms.

4r + 20 = 360                         Subtract 20 from both sides

4r + 20 - 20 = 360 - 20          Collect terms

4r = 340                                   Divide by 4

r = 340 / 4                                do the division

r = 85          

Answer

r + 10 = 85 + 10 = 95

Answer 95 km/hr

if im undersanding the question correctly, its organized from 10

step-by-step explanation:

true

step-by-step explanation: