Students are entering an auditorium at a constant rate .when the auditorium opens there are already 23 students sitting in it after it has been feeling for 10 minutes there are now 473 students in the auditorium. find average rate of change for the first 10 minutes how many students will be in the auditorium after 15 minutes of filling

There are 698 students in the auditorium after 15 minutes.

Given information:

Students are entering an auditorium at a constant rate.

At the initial phase, there are 23 students in the auditorium.

After it has been feeling for 10 minutes, there are now 473 students in the auditorium.

So, in 10 minutes, the number of students entered the auditorium is,

So, the rate at which the students are entering the auditorium will be,

So, after 15 minutes, the number of students in the auditorium will be,

Therefore, there are 698 students in the auditorium after 15 minutes.

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Let the rate be r, in units of students per minute.  After 0 minutes, we have 23 students, After t minutes, we have

s = rt + 23

When t=10 we have s=473

473 = 10r + 23

450 = 10r

r = 45 students per minute

Answer [first part]: 45 students per minute

When t=15, we get

s = 45(15) + 23 = 698

Answer [second part]: 698

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.

answer: you need to organize this better it does not make sense.

step-by-step explanation: ?