You want to make five-letter codes that use the letters a, f,e, r, and m without repeating any letter. what is the probability that a randomly chosen code starts with m and ends with e?

The theoretical definition of the probability is

1. The number of all possible outcomes.

You have 5 letters. The first letter of the code can be chosen in 5 ways, the second - in 4 ways, the third - in 3 ways, the fourth letter - in 2 ways and the last one - in 1 way. In total, the number of all possible outcomes is

2. The number of all favorable outcomes.

If the code starts with M and ends with E, then you can change only second, third and fourth letters of the code. The second letter can be chosen in 3 ways (from letters A, F and R), the third letter - in 2 ways and the fourth letter - in 1 way. In total,  the number of all favorable outcomes is

Then the probability is

answer:   expression= p+p*d%

price reduction + sale price = $625

sale price: $p+$p*d%

where d% is the percentage of discount

step-by-step explanation:

original price = p

price went down by $150 price reduction $p*d%

sale price= $ 475

therefore the price before sale is: $625

and the expression that shows the price before sale is: p+p*d%

d. corresponding side lengths in similar triangles are proportional in length.

step-by-step explanation: