How do u fully factor 3(x+5)^2 + 27(x-5)-66 the answer is 3(x+6)(x-7) pls show steps ?

First simplify the equation by distibuting

3(x+5)(x+5) + 27(x-5)-66 becomes

3x^2 + 30x + 75 + 27x - 135 - 66

simplify

3x^2 + 57x - 126

factor out a gcf

3(x^2 + 19x - 42)

then factor once more to recieve

3(x + 2)(x -21)

Did you write the problem incorrectly?

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step-by-step explanation: