Abusiness buys a computer for $3,000. after 4 years the value of the computer is expected to be $250. the value, v, can be related to the time in years, t, in a linear equation. which equation models the relationship between v an t? a. v=250t b. v=-250t c. v=687.50t-3,000 d. v=-687.50t+3,000

You are given two points in the linear function. At time 0 years, the value is $3000. At time 4 years, the value is $250. This means you have points (0, 3000) and (4, 250). You need to find the equation of the line that passes through those two points.

y = mx + b

m = (y2 - y1)/(x2 - x1) = (3000 - 250)/(0 - 4) = 2750/(-4) = -687.5

Use point (0, 3000).

3000 = -687.5(0) + b

b = 3000

The equation is

y = -687.5x + 3000

Since we are using points (t, v) instead of (x, y), we have:

v = -687.5t + 3000

d. v = -687.50 t + 3,000

step-by-step explanation:

; fx

answer: yes, since the line has a steeper rate of change than the exponential the y-values will be greater and they will only intersect one time.