Mathematics, 01.07.2019 02:00 bvghchg8812

Can someone 1. add or subtract as indicated. write the answer in descending order. (3n4 + 1) + (–8n4 + 3) – (–8n4 + 2) 2. write the number in standard notation: 6.5 × 10–7 3. translate from algebraic form to english form. (m – n)(m + n) 4. (–3t2u3)(5t7u8) = 5. complete the property of exponents. bn ⋅ bm = 6. divide the polynomials by using long division. (x3 – x2 – 2x + 14) ÷ (x – 1) 7. evaluate the rational function, if possible. m[y]=2y+5/y-7 , m[7] 8. factor out the greatest common factor. 30t2u + 12tu2 + 24tu

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ANSWER TO QUESTION 1

$(3 {n}^{4} + 1) + ( - 8 {n}^{4} + 3) - ( - 8 {n}^{4} + 2)$

Let us expand the parenthesis first.

$(3 {n}^{4} + 1) + ( - 8 {n}^{4} + 3) - ( - 8 {n}^{4} + 2) = 3 {n}^{4} + 1 + - 8 {n}^{4} + 3 + 8 {n}^{4} - 2$

This will simplify to,

$(3 {n}^{4} + 1) + ( - 8 {n}^{4} + 3) - ( - 8 {n}^{4} + 2) = 3 {n}^{4} + 2$

ANSWER TO QUESTION 2

We want to write
$6.5 \times 10 - 7$

in standard notation.

Let us simplify first to obtain,

$6.5 \times 10 - 7 = 65 - 7$

$6.5 \times 10 - 7 = 58$

In standard notation we have,

$6.5 \times 10 - 7 = 5.8 \times {10}^{1}$

$6.5 \times 10 - 7 = 5.8 \times {10}$

ANSWER TO QUESTION 3

This question requires us to write (m-n)(m+n)

in words.

Subtract

from

and multiply the result by the sum of

and

.

ANSWER TO QUESTION 4

We want to simplify

$( - 3 {t}^{2} {u}^{3} )(5 {t}^{7} {u}^{8} ).$

We use the laws of exponents to simplify the above expression.

$( - 3 {t}^{2} {u}^{3} )(5 {t}^{7} {u}^{8} ) = - 3 \times 5 \times {t}^{2} \times {t}^{7} \times {u}^{3} \times {u}^{8}$

Recall that,

${a}^{m} \times {a}^{n} = {a}^{m + n}$

This implies that,

$( - 3 {t}^{2} {u}^{3} )(5 {t}^{7} {u}^{8} ) = - 15 \times {t}^{2 + 7} \times {u}^{3 + 8}$

This simplifies to,

$( - 3 {t}^{2} {u}^{3} )(5 {t}^{7} {u}^{8} ) = - 15 \times {t}^{9} \times {u}^{11}$

ANSWER TO QUESTION 5.

We want to complete the property of exponents given by,

${b}^{n} \times {b}^{m}$

According to this product property of exponents,since the bases are the same we write down one base and add the exponents to obtain,

${b}^{n} \times {b}^{m} = {b}^{m + n}$

ANSWER TO QUESTION 6.

Please see attachment for the long division

ANSWER TO QUESTION 7.

We were given the expression,

$m(y) = \frac{2y + 5}{y - 7}$

This is a rational expression. The expression is not defined for
y = 7

Therefore it is not possible to evaluate
m(7)

Evaluating this will result in division by zero as shown below.

$m(7) = \frac{2(7) + 5}{7 - 7}$

$m(7) = \frac{19}{0}$
ANSWER TO QUESTION 8.

We want to factor the Greatest Common Factor out of
$30 {t}^{2} u + 12t {u}^{2} + 24tu$
The greatest common factor is
6tu

We factor it to obtain,

$30 {t}^{2} u + 12t {u}^{2} + 24tu = 6tu(5t + 2u + 4)$
Can someone 1. add or subtract as indicated. write the answer in descending order. (3n4 + 1) + (–8

Answer from: Quest

answerthe vertex form

step-by-step explanation:

Answer from: Quest

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range:

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