How do you find the area of the field in terms of x

Hello from MrBillDoesMath!

 104x^2 + 166x + 66

Discussion:

The area of a rectangle is given by "length" * "width". For us the formula becomes

 (13x + 11) * (8x+6)

or

13x (8x +6) + 11 * (8x + 6)  =

(13x * 8x + 13x* 6) + ( 11*8x + 11*6) =

(104x^2 + 78x ) + (88x + 66) =

104x^2 + (78x + 88x) + 66 =

104x^2 + 166x + 66

Thank you,

MrB

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.