There are two parking garages in beacon falls . garage a charges $7.00 to park for the first 2 hours ,and each additional hour costs $3.00. garage b charges $3.25 per hour to park. when a person parks for at least 2 hours , write equations to model the cost of parking for a total of x hours ib garage a and garage b. determine algebraically the number of hours when the cost of parking at both garages will be the same.

Answer

Find out the number of hours when the cost of parking at both garages will be the same.

To prove

As given

There are two parking garages in beacon falls .

As given

Let us assume that the y is representing the  cost of parking at both garages will be the same.

The total number of hours is represented by the x.

First case

Garage a charges $7.00 to park for the first 2 hours ,and each additional hour costs $3.00 .

As  garage charges $7.00 for the first 2 hours so the remaning hours are (x -2)

Than the equation becomes

y = 3.00 (x -2) + 7.00

written in the simple form

y = 3x - 6 +7

y = 3x + 1

Second case

Garage b charges $3.25 per hour to park.

than the equation becomes

y = 3.25x

Compare both the equations

3x +1 = 3.25x

3.25x -3x = 1

.25x = 1

x = 4hours

Therefore in the 4 hours  the cost of parking at both garages will be the same.

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

a) 0

step-by-step explanation:

i^413 x i^0 = 0 as any number multiplied by a zero is

happy to

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