Afigure skating school offers introductory lessons at $25 per session. there is also a registration fee of $30. write a linear equation in slope- intercept firm that represents the situation. you want to take at least 6 lessons. can you pay for those lessons using a $200 gift certificate? if so, how much money, if any, will be left on the gift certificate? if not, explain why not

y = $25/session . x + $30

You can pay with a $200 gift certificate and there will be $20 left.

Step-by-step explanation:

Let's call

The slope-intercept form of the linear equation has the following form.

y = a . x + b

where,

a is the slope

b is the y-intercept

The slope represents how much you pay per session, that is, a = $25/session.

Before starting your first lesson (x = 0), you have to pay the registration fee (y = $30). Then

$30 = $25/session . 0 + b

b = $30

The linear equation is

y = $25/session . x + $30

If you  want ot take 6 lessons (x = 6),

y = $25/session . 6 + $30

y = $180

You can pay with a $200 gift certificate and there will be $200 - $180 = $20 left.

$20 will be left on the gift certificate.

Step-by-step explanation:

The cost per session = $25

so the slope of the equation that represent the situation is 25

Registration fee = $30

so y-intercept is 30

An equation is:

The cost for 6 lessons is

A $200 gift certificate would pay for the lessons.

And $20 would be left.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?