Use the remainder theorem to completely factor p(x) = x^3 - 6x^2 + 11x - 6. show your work.

p(x) = (x - 1)(x - 2(x - 3)

note that p(1) = 1 - 6 + 11 - 6 = 0

x = 1 is a root ⇒ (x - 1 ) is a factor

1 | 1 - 6 + 11 - 6

   ↓   1 - 5   +6

    1  - 5 6   0

p(x) = (x - 1)(x² - 5x + 6 ) = (x - 1)(x - 2)(x - 3)

step-by-step explanation:

i think you should think about the question and not look online.

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1