Which statement regarding the graph is true? which of the following statements is true? the store sold 4,000 fewer units in november than in august. more customers prefer chocolate than strawberry and vanilla combined. yogurt sales had a decreasing trend during the last four months of 2011.the median number of ounces sold from 3 to 4 p. m. was more than the median number sold from 7 to 8 p. m

Which statement regarding the graph is true? Which of the following statements is true?

Question:

The store sold 4,000 fewer units in November than in August.

FALSE.

Explanation:

Number of units sold in November = 3000

Number of units sold in August = 6000

difference in both = 6000-3000= 3000

which not same as 4000 hence wrong

Question:

More customers prefer chocolate than strawberry and vanilla combined.

FALSE.

Explanation:

value for Chocolate is 38% which is clearly less than combined value of strawberry (30%)  and vanilla (22%). which is (30+22=52%)

Question:

Yogurt sales had a decreasing trend during the last four months of 2011.

TRUE

Explanation:

Graph is going down ward for the last four months (sept to Dec) which means decreasing sales.

Question:

The median number of ounces sold from 3 to 4 p.m. was more than the median number sold from 7 to 8 p.m

FALSE.

Explanation:

It is not true for all Stem values.

Like when stem =1, then (3 to 4 p.m.) has median =0

but for (7 to 8 p.m) has median 6 which is more than 3 to 4 pm  

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}