Arectangle has a perimeter of 6x^3+9x^2-10x+7 and a length of x. find the width of the rectangle when the length is 19 inches

Using the perimeter concept, it is found that:

The width of the rectangle is of 22091 inches.

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Perimeter of a rectangle:

The perimeter of a rectangle of length l and width w is given by:

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Since the length is 19:

And

The width of the rectangle is of 22091 inches.

A similar problem is given at link

Width =  21731 inches .

Step-by-step explanation:

Given  : A rectangle has a perimeter of 6x³+9x²-10x+7 and a length of x.

To find : find the width of the rectangle when the length is 19 inches

Solution : We have given

Perimeter = 6x³+9x²-10x+7

x = length

Length = 19.

Width = w .

By the formula of perimeter :

Perimeter = 2 ( length + width)

Plugging the values

6x³+9x²-10x+7 = 2 ( 19 + w).

x = 19 inches.

6(19)³+9(19)²-10(19)+7 = 2( 19 + w).

6(6859) + 9 ( 361) - 190 + 7 = 2 ( 19 + w).

41154 + 3249 -190 + 7 = 2 ( 19 + w).

43500  = 2 ( 19 + w).

On dividing both sides by 2

21750 = 19 + w.

On subtracting both sides by 19

w = 21750 -19.

w = 21731 inches.

Therefore, Width =  21731 inches .

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