Write the equation of the line that goes through points (9, 1) and (-1, 6) in slope-intercept form. (hint: find slope first and then use y = mx + b).

First things first, you need to find the gradient which is:

Take (9 , 1) , 9 = x₁ and 1 = y₁

Also means that in ( -1, 6 ) , -1 = x₂ and 6 = y₂

Simply plug these values into the formula:

Which simplifies to:

Which then also simplifies down to:

So the gradient is , so mx - x

Now plug this into y = mx + b with one point, such as ( 9 , 1) where 1 is y and x is 9:

1 = ( x 9) + b

Which means that this can be rearranged to make 'b' the subject, making sure the positive negative half is made positive:

1 + 4.5 = b

So the intercept is b

This would then make the y = mx + b:

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.