1. what is an equation of a line, in point-slope form, that passes through (1,-7) and has a slope of -2/3? 2. what is the equation of a line, in point-slope form, that passes through (-2,-6) and had a slope of 1/3? 3. what is an equation in point-slope form of the line that passes through the points (4,5) and (-3,-1)? 4. what is the equation in point-slope form of a line that passes through the points (5,-3) and (-2.9) 5. plot the line for the equation on the graph. y-5=3/2(x-2) me complete all of them, you so much!

1. What is an equation of a line, in point-slope form, that passes through (1,-7) and has a slope of -2/3?

Point Slope form y − y1 = m(x − x1)

Y1: -7 x1:1 slope :-2/3

Y-(-7)=-2/3(x-1)

Y+7=-2/3(x-1)

2. What is the equation of a line, in point-slope form, that passes through (-2,-6) and had a slope of 1/3?

Y-(-6)=1/3(x-(-2))

Y+6=1/3(x+2)

3.What is an equation in point-slope form of the line that passes through the points (4,5) and (-3,-1)

SlopeM: =change in y/change in x

M= -1-5/-3-4

M= -6/-7

M=6/7

So now slope:6/7, point (4,5)

Y-y1=m(x-x1)

Equation in point slope

Y-5=6/7(x-4)

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3