Mathematics, 01.07.2019 09:30 dpchill5232
What is the inverse of the function h(x)= ^5√(6x-12) + 1 ? h(x)= 5th root of (6x -12) + 1
Answers: 1
![\bf \stackrel{h(x)}{y}=\sqrt[5]{6x-12}+1\implies \stackrel{switcheroo}{x=\sqrt[5]{6y-12}+1}\implies x-1=\sqrt[5]{6y-12} \\\\\\ (x-1)^5=6y-12\implies (x-1)^5+12=6y\implies \cfrac{(x-1)^5+12}{6}~~=~~\stackrel{f^{-1}(x)}{y}](/tpl/images/0038/2013/75fcd.png)
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What is the inverse of the function h(x)= ^5√(6x-12) + 1 ? h(x)= 5th root of (6x -12) + 1...
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