The x-intercept is the x-coordinate of the point where a graph crosses the x-axis. what is the slope of a line that has a y-intercept but no intercept? explain. all i can come up with is that the line is a vertical line starting from any y-intercept and in this case the answer would be undefined. is there a better answer?

The slope of a line that has a y-intercept, but no x-intercept is 0.

Step-by-step explanation:

A line that crosses the y-axis but not the x must be horizontal. Therefore, it has no slope.

In the example that you were working on, it will have an x-intercept. All vertical lines will hit the x-axis. An undefined line would likely have no y-intercept.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15