At noon a car leaves washington, d. c., headed for miami, florida, a distance of 1100 miles. the train travels at a speed of 60 mph. at 1 pm a second car leaves miami headed for washington d. c., traveling at 70 mph. at what time will the two trains pass each other?

I car starts at 12.00 noon

Distance between Washington and Miami = 1100 miles

Speed = 60 mph

Hence after 1 hour, I car will be at 60 miles from Washingon or (1100-60) = 1040 miles from Miame.

At 1.00 p.m. distance between two cars is 1040 miles.

Since cars travel at opposite directions, relative speed per hour = addition of two speeds = 60+70 = 130 mph

Distance = 1040 miles

Relative speed =130 mph

Hence time for their meeting = 1040/130 = 8 hours

i.e. At 9 p.m. both will meet.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

30 units^2

step-by-step explanation:

area is l × w

the length is 3

and the width is 10

3 × 10= 30 units squared