Which of the following is the equation of a line that is parallel to y=5x-3 and that passes through the point (2,5)

parallel to the line y = 5x - 3, so the other lines must have same slope m = 5

y - y1 = m(x - x1)

y - 5 = 5(x-2)

y = 5x - 10 + 5

y = 5x - 5

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

well what did you do it matters what you did : )

step-by-step explanation: