If you divide one of the roots of the equation 4x2+bx−27=0 by the other root, the quotient will be −3. find b.

  ±12   (two answers)

Suppose one root is a. Then the other root will be -3a. The product of the two roots is the ratio of the constant coefficient to the leading coefficient:

  (a)(-3a) = -27/4

  a² = -27/(4·(-3)) = 9/4

  a = ±√(9/4) = ±3/2

Then the other root is

  -3a = -3(±3/2) = ±9/2 . . . . . . the roots will have opposite signs

We know the opposite of the sum of these roots will be the ratio of the linear term coefficient to the leading coefficient: b/4, so ...

  -(a + (-3a)) = b/4

  2a = b/4

  b = 8a = 8·(±3/2)

  b = ±12

Check

For b = 12, the equation factors as ...

  4x² +12x -27 = (2x -3)(2x +9) = 0

  It has roots -9/2 and +3/2, the ratio of which is -3.

For b = -12, the equation factors as ...

  4x² -12x -27 = (2x +3)(2x -9) = 0

  It has roots 9/2 and -3/2, the ratio of which is -3.

it's 12 and -12

Step-by-step explanation:

i didnt know there was two answers, and i was so confused

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

answer: sine

step-by-step explanation: