What is the volume of a frustum of a rectangular pyramid if one base has measurements 6 ft. × 8 ft., the other base has measurements 14 ft. × 18 ft., and the height is 3 ft.? a. 120.98 ft.3 b. 560.30 ft.3 c. 409.98 ft.3 d. 252.8 ft.3

C. 409.98 ft³

The formula for the volume of a frustum is ...

... V = (h/3)(B₁ + √(B₁B₂) + B₂)

where B₁ and B₂ are the areas of the bases.

Here, we have ...

... B₁ = (6 ft)(8 ft) = 48 ft²

... B₂ = (14 ft)(18 ft) = 252 ft²

So the volume is ...

... V = (3 ft)/3 × (48 ft² + √(48·252) ft² + 252 ft²) ≈ 409.98 ft³

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation: