What is the y-intercept of the equation of the line that is perpendicular to the line y =3/5x + 10 and passes through the point (15, –5)? the equation of the line in slope-intercept form is y = -5/3x + .

Equation of the line in the slope-intercept form will be

Step-by-step explanation:

An equation of the line perpendicular to will be in the form of y = mx + c

Where m = slope of the line

c = y intercept of the line

From the property of the perpendicular line

where and are the slopes of the perpendicular lines.

If   =

then

So the equation will be

This line passes through the point (15, -5)

-5 = -25 + c

c = 25 - 5

c = 20

Finally the equation will be

damm bro the struggle

step-by-step explanation:

the answer is 11.2 (i know i’m late)