Pq is a tangent segment of a circle with radius 9 in. q lies on the circle, and pq = 13 in. find the distance from p to the circle. if necessary, round to the nearest tenth of an inch. you may find making a sketch in solving this problem.

6.8 inches

The shortest distance from P to the circle is along the line between P and the center of the circle. That line is the hypotenuse of the right triangle whose legs are PQ and QC (where C is the circle center).

The Pythagorean theorem tells you

... PC² = PQ² +QC²

... PC² = 13² +9² = 250

... PC = √250 = 5√10 ≈ 15.8114 . . . . inches

The distance from P to the circle is 9 in less than this, so is

... 15.8114 - 9 = 6.8114 ≈ 6.8 . . . . inches

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64

6x = 48

i hope this . 6 cards each and a total of $48. dvide each side by 6 and you will have your answer.