Robert took out an 80/20 mortgage to buy a $145,000 house. the first (80%) mortgage has an interest rate of 4.75%, and the second (20%) mortgage has an interest rate of 7.525%. both mortgages are 30-year fixed-rate mortgages. what is the total mortgage payment for this house?

$808.38

The formula for the payment amount (A) on principal P at interest rate r compounded monthly for a loan period of t years is ...

... A = P(r/12)/(1 -(1 +r/12)^(-12t))

For the main loan, the payment is ...

... A = 0.80·145000·(.0475/12)/(1 -(1 +.0475/12)^(-12·30)) = 605.11

For the piggyback loan, the payment is ...

... A = 0.20·145000·(.07525/12)/(1 -(1 +.07525/12)^(-12·30)) = 203.27

So, the total of monthly payments for the two loans is ...

... $605.11 +203.27 = $808.38

$808.38

Step-by-step explanation:

<3

-4

step-by-step explanation:

(-4+8)=-(4-8)=-8+4=-4

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°