What is the answer to these simultaneous equations?

Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

Let's write down the equations which we will be solving as displayed below:

Equation No. 1 -

4m + n = 6

Equation No. 2 -

3m = 2n - 13 / 2

To begin with, we will make ( n ) the subject in the first equation as displayed below:

Equation No. 1 -

4m + n = 6

n = 6 - 4m

Next, we will substitute the value of ( n ) from the first equation into the second equation and also make ( m ) the subject. Then, we will solve the equation as displayed below:

Equation No. 2 -

3m = 2n - 13 / 2

3m = 2 ( 6 - 4m ) - 13 / 2

3m = 12 - 8m - 13 / 2

3m + 8m = 12 - 13 / 2

11m = 11 / 2

m = ( 11 / 2 ) ÷ 11

m = 1 / 2

Now we will substitute the value of ( m ) from the second equation into the first equation as displayed below:

Equation No. 1 -

n = 6 - 4m

n = 6 - 4 ( 1 / 2 )

n = 6 - 2

n = 4

ANSWER:

Therefore, our answer is:

m = 1 / 2

n = 4

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The answer is b 12-4m