The average snow fall in lake hopatcong is normally distributed. the average snowfall equals 56 inches. the average snow fall in lake hopatcong exceeds 59 inches in 15% of the year. what is the standard deviation?

Solution: We are given that average snowfall in lake Hopatcong is normally distributed with mean inches

The average snowfall in lake Hopatcong exceeds 59 inches in 15% of the year.

Therefore, the z score corresponding to less 59 inches is

Using the z-score formula, we have:

rounded to 3 decimal places

Hence the standard deviation is 2.895 inches

using pemdas, (order of operations) you'll see the answer is 24.