Find m< 2 if m< 1 = 100 and m< 6 = 128. answers and figure attached!

<6 +<3 =180  straight line

128+<3 =180

subtract 128 from each side

<3 = 180-128

<3 = 52

<1 + <2 + <3 = 180  sum of the angles of a triangle

100 + <2 + 52  = 180

152 +<2 = 180

subtract 152 from each side

<2 = 180-152

<2 =28

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204