Geometry: asap pls - show all work ( only answer if you know the answer) find the distance between the points to the nearest tenth. 1. c(-1, -1), d(6, 2) 2. e(-7, 0), f(5 ,8) line ab has endpoints a(-3, 2) and b(3, -2). 3. find the coordinates of the midpoint of line ab 4. find ab to the nearest tenth

Find the distance between the points to the nearest tenth.

1. C(-1, -1), D(6, 2)  Think of a right triangle whose hypotenuse connects. C and D; the length of this hypotenuse is the distance between C and D.  As we go from C to D, x increases by 7 and y increases by 3.  These distances represent the lengths of the shorter two legs of the right triangle.  Then, according to the distance formula (which is essentially the same thing as the Pythagorean Theorem):  3^2 + 7^2 = distance^2.  This becomes distance^2 = 9 + 49, or distance^2 = sqrt(58).  The distance from C to D is sqrt(58) units.

2. E(-7, 0), F(5 ,8)  Following the same reasoning and same approach, the distance between E and F is sqrt(12^2 + 8^2), or sqrt(144+64), or sqrt(208).  This reduces to sqrt (4*52), or 2sqrt(52).  The distance from E to F is 2sqrt(52).

Line AB has endpoints A(-3, 2) and B(3, -2).

3. find the coordinates of the midpoint of Line AB.  Use the midpoint formulas to find the coordinates of the midpoint of the line connecting A and B.  The x-coordinate is (-3+3)/2, or 0.  The y-coordinate is (2-2)/2, or 0.  Thus, the midpoint of AB is (0,0).

4. Find AB to the nearest tenth.  Follow the same reasoning and approach used in (1) and (2) above:  change in x = 6; change in y = -4.  Then the distance between A and B (that is, the length of AB) is: sqrt(36+16) =sqrt(52), or, to the nearest tenth, 7.2.

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages