The sum of three consecutive integers is 31 more than the largest integer. find the integers

To solve with an equation, let's call the three consecutive integers g, g+1, and g+2.

So, (g)+(g+1)+(g+2)=(g+2)+31

3g + 3 = g + 33

2g = 30

g = 15

The integers are 15, 16, and 17.

To check:

The sum of 15, 16, and 17 is 48. 17 + 31 is also 48.

Let's express this in algebraic terms:

The expressions for the integers and respective values are expressed below:

Now, to check, we apply the original problem and the values we discovered:

We are right, so:

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

answer: hey there,

the answer you are looking for is a..

hope this you!