The length of a line segment is m. this segment is divided into: a) three equal parts; b) five equal parts. find the distance between the midpoints of the first and the last parts in each case. i need the correct answer tysm if you answer!

Consider the case where each part is of length 1. Then the midpoint of the first segment is at 1/2.

a) If there are 3 segments, the midpoint of the last segment is halfway between 2 and 3, at 2 1/2. The distance from the first midpoint to the last midpoint is ...

... 2 1/2 - 1/2 = 2 . . . . . that is, 2/3 of the total line length

When the line length is m, that is 2/3·m

b) If there are 5 segments, the midpoint of the last segment is halfway between 4 and 5, at 4 1/2. The distance from the first midpoint to the last midpoint is ...

... 4 1/2 - 1/2 = 4 . . . . . that is, 4/5 of the total line length

When the line length is m, that is 4/5·m

step-by-step explanation:

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is           symmetric about the line y = 120,000.

step-by-step explanation:

given that megan owns a clothing boutique.

the profits of 2010, 11, are recorded and shown as follows:

years since     2010 0     1     2     3       4       5

profits made in 1000's   39       84     111     120   111     84

we find that profit gradually increases form 2010 to 2013 upto 120,   then starts decreasing.

the profits for 2012 and 2014 are the same while that of 2011 and 2015 are also the same.

this shows that there is symmetry about the line profit = 120000

hence answer is:

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is           symmetric about the line y = 120,000.

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just needed some points but try socratic