In δabc, m∠abc = 40°, bl is the angle bisector of ∠b with point l∈ ac . point m ∈ ab so that lm ⊥ ab and n ∈ bc so that ln ⊥ bc find the angles of △mnl

It can help to draw a diagram.

∆LBM ≅ ∆LBN by the hypotenuse-angle (HA) theorem of congruence of right trianges. Then LM ≅ LN and BM ≅ BN by CPCTC. Quadrliateral BMLN is a kite,  so diagonal MN ⊥ BL.

Of course, angles BLN and BLM are the complements of the halves of bisected angle B, so are both 70°. And angles LMN and LNM are the complements of those, so are both 20°.

∆MNL is an isosceles triangle with base angles of 20° and an apex angle of 140°.

3.76%

step-by-step explanation:

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