60 ’s sandwich shop sells wraps and sandwiches as part of its lunch specials. the profit on every sandwich is $2 and the profit on every wrap is $3. sal made a profit of $1,470 from lunch specials last month. the equation 2x + 3y = 1,470 represents sal’s profits last month, where x is the number of sandwich lunch specials sold and y is the number of wrap lunch specials sold. 2. describe how you would graph this line using the slope-intercept method. be sure to write in complete sentences. 3. write the equation in function notation. explain what the graph of the function represents. be sure to use complete sentences.

2x + 3y = 1,470

To solve using the slope intercept method, we need to solve for y.

First, subtract 2x from each side.

3y = -2x +1470

The, we need to divide both sides of the equation by by 3 to solve for y

y = -2/3 x + 490.

We know the y intercept is 470, which means on the y axis we place at point at positive 490.  The slope is -2/3.  We go down 2 units and over to the right 3 units and place a point.  We draw a line connecting these two points extending only to the right until it reaches the x axis. We cannot have negative x because we cannot sell negative lunch specials.  We cannot have negative y, because y is the number of specials sold.

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300

it has the same slope and a different y-intercept

hope this : )