Mathematics, 02.07.2019 14:30 Emiann222

The jogging track at francine’s school is 3/4 mile long. yesterday francine completed two laps on the track. if she ran 1/3 of the distance and walked the remainder of the way, how far did she walk?

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Answer from: Jabari8728

1 mile

Step-by-step explanation:

Given: The jogging track at Francine’s school is $\frac{3}{4}$ $\text{mile}$ long. Yesterday Francine completed two laps on the track. If she ran $\frac{1}{3}$ of the distance and walked the remainder of the way.

To Find: how far did she walk

Solution:

Length of jogging track at Francine’s school $=\frac{3}{4}$ $\text{mile}$

Let the distance covered by running be $=\text{x}$

Let the distance covered by walking be $=\text{y}$

Total number of laps completed by Francine

Total distance covered by Francine $=\text{number of laps}\times\text{distance covered in one lap}$

$2\times\frac{3}{4}$

$\frac{3}{2}\text{mile}$

Now,

distance covered by running $=\frac{1}{3}\text{of total distance}$

$\text{x}=\frac{1}{3}\times\frac{3}{2}$

$\text{x}=\frac{1}{2}$ $\text{mile}$

distance covered by walking $\text{y}$ $=\text{total distance}-\text{distance covered by running}$

$\frac{3}{2}-\text{x}$

$\frac{3}{2}-\frac{1}{2}$

$\text{mile}$

Hence, Francine walked for $\text{mile}$

Answer from: Quest

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a= -1/116

Answer from: Quest

step-by-step explanation:

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