The perimeter of a rectangle is 72 cm. the length, l, of the rectangle is 6 cm longer than the width, w. what is the width of the rectangle? a. 10 cm b. 8 cm c. 15 cm d. 33 cm

Let l be the length and w be the width of the rectangle.

It is given that the perimeter is 72 cm.

Therefore, 2(l + w) = 72

Divide both sides by 2.

l + w = 36

It is also given that the length l is 6 cm longer than the width, w.

Therefore, l = w + 6

Now, (w + 6) + w = 36

(w + w) + 6 = 36

2w + 6 = 36

2w = 36 - 6

2w = 30

Divide both sides by 2.

w = 15

Hence, the width of the rectangle is 15 cm. and it is given in option C.

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm