What is the area of the triangle whose vertices are d( 3, 3), e(3, -1), and f(-2, -5)? show all your work! your choice of method on how to find the area.

Answer-

Area of the triangle is 10 sq.units

Solution-

We know that,

Taking,

(x₁, y₁) = (3, 3)

(x₂, y₂) = (3, -1)

(x₃, y₃) = (-2, -5)

Then putting these in the formula,

As area can not be negative, ignoring negative sign,

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )