Create a two-column proof: given: eab and dcb are two right triangles. the figure has bed≅ bde. point b is the midpoint of segment ac. prove: eab≅ dcb

Proved with RHS congruency rule.

Step-by-step explanation:

Given ΔEAB and ΔDCB are two right triangles. The figure has ∠BED≅ ∠BDE. Point B is the midpoint of segment AC.

We have to prove that ΔEAB ≅ ΔDCB

In ΔEAB and ΔDCB

BE=BD   (∵∠BED≅ ∠BDE)

AB=BC    (given B mid-point)

By RHS congruency rule which states that two right triangles are congruent if the hypotenuse and one side of triangle are respectively equal to the hypotenuse and the corresponding side of the other triangle.

Hence, By RHS rule

ΔEAB ≅ ΔDCB

Hence Proved.

sine

step-by-step explanation:

c

step-by-step explanation:

i think because what else can be a sample of every member