Find the measure of each acute angle in a right angle where the measure of one acute angle is 5 times the measure of the other acute angle

We are given that the measure of one acute angle is 5 times the measure of the other acute angle.

Let us assume the measure of the other acute angle = x degree.

First acute angle is 5 times the other, that is  = 5x degrees.

Both angles are making a right angle.

A right angle sum upto 90 degrees.

Therefore,

x+5x = 90.

6x = 90.

Dividing both sides by 6, we get

x =15.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

126 maybe. sorry