Rewrite with only sin(x) and cos(x). sin(3x)

sin 3x = sin (2x + x)

= sin2x cos x + cos 2x sin x   (using the compound angle identity)

= 2sin x cos x.cos x  (1 - 2sin^2x) sinx     (using identities for sin2x and cos2x)

=  2 sin cos^2 x + sin x - 2 sin^3 x

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

k

step-by-step explanation:

domit