Given the equation -5x+2y=-10 what is the equation of the line perpendicular to the line? given the equation -5x+2y=-10 what is the equation of the line perpendicular to the line that goes through the point (-5,1) show work and step by step for both

The equation of the perpendicular line would be y = -2/5x - 1

Step-by-step explanation:

In order to find this line, we must first find the slope of the original line. We do this by solving for y.

-5x + 2y = -10

2y = 5x - 10

y = 5/2x - 5

This shows us a slope of 5/2. TO find the perpendicular slope, we use the opposite and reciprocal. This means we negative 5/2 to get -5/2 and then we flip it to get -2/5. Now that we have this, we can use the slope and the point in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 1 = -2/5(x + 5)

y - 1 = -2/5x - 2

y = -2/5x - 1

ok thats very interesting