Aconvex hexagon has exterior angles that measure 80, 68, 84°, 56°, and 40°. which of the following is the measure of the sixth exterior angle?

The measure of the sixth exterior angle of the hexagon will be 32°.

It is because sum of exterior angles of a closed polygon is 360°.

The remaining sixth exterior angle of the given hexagon.

The sum of all exterior angles of any closed polygon is 360°.

Let the sixth angle of the given hexagon be s°. Then we will have:

Thus, the measure of the sixth exterior angle of the hexagon will be 32°.

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32°

The sum of the exterior angles of a polygon = 360°

Subtract the sum of the 5 given angles and subtract from 360 for sixth exterior angle

360° - (80 + 68 +84 + 56 + 40 ) ° = 32°

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation:

step-by-step explanation: