Write an equation of the line that is perpendicular to y=-2x-3, and psses through the point (2,-2)

Hey there! :)

Perpendicular to y = -2x - 3 ; passes through (2, -2)

Using our given information, let's find the slope.We know that in slope-intercept form, m=slope. So, look at our given equation and see what number is in the "m" spot from y=mx+b.

According to our equation, -2 is our slope! However, because we're looking for an equation that's perpendicular to our given one, we need to use the negative reciprocal of -2.

Keep in mind that a negative reciprocal is a number turned upside down and then given or taken away a negative. Ex : -4 turns into 1/4.

So the reciprocal of -2 is 1/2. Now that we have our new slope ( 1/2 ), we must use this equation to find our new equation. y-y₁=m(x-x₁)

Using the new slope (1/2) & the points (2, -2), we can find our new equation.

y - (-2) = 1/2(x - (2)

Simplify.

y + 2 = 1/2x - 2/2

Simplify.

y + 2 = 1/2x - 1

~Hope I helped!~

d is the answer

step-by-step explanation:

the answer is 8/21

hope this